Oblicz wielomian POMOCY!!!!!!!!: (x³−2)(x³+2)−(2−x)(x+2)(4+2x+x²)(x²−2x+4)+3x³+60

Eta: Zastosuj wzory: (a−b)(a+b)= a² −b² (x³ −2)(x³+2)= x⁶ −4 oraz: ( a−b)(a²+ab+b²)= a³ −b³ (2−x)(4+2x+x²)= 2³−x³= 8−x³ oraz ( a+b)(a²+ab+b²)= a³+b³ ( x+2)(x²−2x +4)= x³ +8 x⁶ −4 − ( 8−x³)( x³+8) +3x³ +60= = x⁶ −4 + ( x³−8)(x³+8) +3x³ +60 ponieważ: ( x³−8)( x³+8) = x⁶ −(8²) = x⁶ −4 + x⁶ − 64 +3x³+60= ........ dokończ